What party did William Sprague belong to?

William Sprague was a member of the Whig party and represented the state of Rhode Island in the U.S. Senate.

When did William Sprague serve in the U.S. Senate?

William Sprague served in the U.S. Senate from February 18, 1842 to January 17, 1844, representing Rhode Island.

When did William Sprague die?

William Sprague died on October 9, 1856.

Historical Profile

William Sprague is no longer an active U.S. Senator. The information below reflects their most recent term.

Whig Inactive

William Sprague

Former U.S. Senator for Rhode Island

Biography

William Sprague (died 1856) was an American politician who represented Rhode Island in the United States Senate from February 1842 to January 1844, during the 27th–28th Congresses. Sprague served as a Whig. Sprague died on October 9, 1856.

Read the U.S. Senate's featured biography of Sprague ↗

Key Information

Full Name: William Sprague
Died: October 9, 1856
Term Started: February 18, 1842
Term Ended: January 17, 1844

Service History

Feb 18, 1842 – Jan 17, 1844 27th–28th Congresses Whig Rhode Island

Service dates from the official U.S. Senate historical roster. For senators who changed party affiliation during their service, the party shown for each period is approximate.

Current Senators from Rhode Island

Served With

Senators who represented the same state during Sprague's service:

James Simmons (RI) 1842–1844